Âû÷èòàíèå çíà÷åíèé COUNT èç SUM |
SELECT Êîíòåéíåðû.Êîíòåéíåð, Sum([Ñïèñàíèå êîíòåéíåðîâ].Êîëè÷åñòâî) - Count([Ïîñòóïëåíèÿ êîíòåéíåðîâ].ÓÊÒÒÈÏ) AS [ÐÀÇÍÈÖÀ] FROM Êîíòåéíåðû, [Ñïèñàíèå êîíòåéíåðîâ], [Ïîñòóïëåíèÿ êîíòåéíåðîâ] WHERE Êîíòåéíåðû.Êîíòåéíåð=[Ïîñòóïëåíèÿ êîíòåéíåðîâ].ÓÊÒÒèï AND Êîíòåéíåðû.Êîíòåéíåð=[Ñïèñàíèå êîíòåéíåðîâ].[Òèï êîíòåéíåðîâ] GROUP BY Êîíòåéíåðû.Êîíòåéíåð
http://www.sql.ru/forum/1153966/vychitanie-znacheniy-count-iz-sum
| Êîììåíòèðîâàòü | « Ïðåä. çàïèñü — Ê äíåâíèêó — Ñëåä. çàïèñü » | Ñòðàíèöû: [1] [Íîâûå] |