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: 16.03.2006
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COUNT SUM

, 27 2015 . 09:53 +
, , .

, . .

SELECT ., Sum([ ].) - Count([ ].) AS []
FROM , [ ], [ ]
WHERE .=[ ]. AND .=[ ].[ ]
GROUP BY .

, . ?

http://www.sql.ru/forum/1153966/vychitanie-znacheniy-count-iz-sum


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