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 LiveInternet.ru:
: 16.03.2006
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, 05 2018 . 10:42 +


. - "_" "__".
:
SELECT .Id_, Sum(_.___) AS [Sum-___], Sum(__.___) AS [Sum-___]
FROM ( INNER JOIN __ ON .Id_ = __.id_) INNER JOIN _ ON .Id_ = _.Id_
GROUP BY .Id_

, , "_" "__" , - .
, "" : "id_"=1, "_" - 2 : "_"=1 2, "__" - 1 : "__"=3
: "id_"=1; "Sum-___"=3; "Sum-___"=6, "Sum-___"=3, "_" 2 , "__" 3+3

,

http://www.sql.ru/forum/1297852/pomogite-s-zaprosom


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