, 16 2015 . 19:03
+
, .
.
:
, . . , . .. , access : " where (count()=2). (, 2 = , , 0 = , 1 = ).
, . , , ?
:
TRANSFORM Sum(_.) AS [Sum-]
SELECT _., _., Count(_.) AS [ ]
FROM _
WHERE (((Count(_.))=2))
GROUP BY _., _.
PIVOT _..;
http://www.sql.ru/forum/1142903/rabota-funkcii-count-v-perekrestnom-zaprose