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 LiveInternet.ru:
: 16.03.2006
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"count" .

, 16 2015 . 19:03 +
, .
.
:
, . . , . .. , access : " where (count()=2). (, 2 = , , 0 = , 1 = ).

, . , , ?

:
TRANSFORM Sum(_.) AS [Sum-]
SELECT _., _., Count(_.) AS [ ]
FROM _
WHERE (((Count(_.))=2))
GROUP BY _., _.
PIVOT _..;

http://www.sql.ru/forum/1142903/rabota-funkcii-count-v-perekrestnom-zaprose


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