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 LiveInternet.ru:
: 16.03.2006
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TRANSFORM PIVOT

, 30 2015 . 11:51 +
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TRANSFORM Count(INN.INN) AS [ ]
SELECT BIK.NAME AS , BIK.BIK AS [ ]
FROM BIK LEFT JOIN INN ON BIK.BIK = INN.BIK
GROUP BY BIK.BIK, BIK.NAME
ORDER BY BIK.NAME
PIVOT INN.NAME;

http://www.sql.ru/forum/1139987/transform-i-pivot


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