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: 16.03.2006
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, 21 2014 . 22:49 +
, , managers id?

SELECT managers.
FROM managers INNER JOIN [1_a] ON managers.[id_ ] = [1_a].[id_ ]
GROUP BY managers.;


ID





http://www.sql.ru/forum/1090485/tablica-s-polyami-so-svyaznoy-tablicy


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