Сопоставление данных с четырёх таблиц |
SELECT T_Scans_Linked.id AS SL_ID, T_Scans_Linked.id_work AS SL_IW, T_Scans_Linked.Content AS SL_Content, T_Scans.id AS S_ID, T_Scans.id_work AS S_IW, T_Scans.Content AS S_Content FROM (T_ID_Works INNER JOIN T_Scans ON T_ID_Works.id = T_Scans.id_work) INNER JOIN (T_ID_Works_Linked INNER JOIN T_Scans_Linked ON T_ID_Works_Linked.id = T_Scans_Linked.id_work) ON T_ID_Works.Work_Code = T_ID_Works_Linked.Work_Code;
http://www.sql.ru/forum/1088519/sopostavlenie-dannyh-s-chetyryoh-tablic
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