$\backslash sin\; \backslash frac\{\backslash pi\}\{10\}\; =\; \backslash sin\; 18^\backslash circ\; =\; \backslash frac\{\backslash sqrt\{5\}-1\}\{4\}$

$\backslash sin\; \backslash frac\{\backslash pi\}\{12\}\; =\; \backslash sin\; 15^\backslash circ\; =\; \backslash frac\{\backslash sqrt\{6\}-\backslash sqrt\{2\}\}\{4\};\; \backslash qquad$
\cos \frac{\pi}{12} = \cos 15^\circ = \frac{\sqrt{6}+\sqrt{2}}{4}

$\backslash operatorname\{tg\}\; \backslash frac\{\backslash pi\}\{12\}\; =\; \backslash operatorname\{tg\}\; 15^\backslash circ\; =\; 2-\backslash sqrt\{3\};\; \backslash qquad$
\operatorname{ctg} \frac{\pi}{12} = \operatorname{ctg} 15^\circ = 2+\sqrt{3}

$\backslash operatorname\{tg\}\; \backslash frac\{\backslash pi\}\{120\}=\; \backslash operatorname\{tg\}\; 1.5^\backslash circ\; =\backslash sqrt\{\backslash frac\{8-\backslash sqrt\{2(2-\backslash sqrt\{3\})(3-\backslash sqrt\{5\})\} —\; \backslash sqrt\{$
2(2+\sqrt{3})(5+\sqrt{5})}}{8+\sqrt{2(2-\sqrt{3})(3-\sqrt{5})}+\sqrt{2(2+\sqrt{3})(5+\sqrt{5})}
}}

$\backslash cos\; \backslash frac\{\backslash pi\}\{240\}=\backslash frac\{1\}\{16\}\backslash left(\backslash sqrt\{2-\backslash sqrt\{2+\backslash sqrt\{2\}\}\}\; \backslash left(\backslash sqrt\{2(5+\backslash sqrt\{5\})\}+\backslash sqrt\{3\}-\backslash sqrt\{15\}\; \backslash right)\; +\; \backslash sqrt\{2+\backslash sqrt\{2+\backslash sqrt\{2\}\}\}\; \backslash left\; (\backslash sqrt\{6(5+\backslash sqrt\{5\})\}+\backslash sqrt\{5\} —\; 1\; \backslash right)\; \backslash right)$

$\backslash cos\; \backslash frac\{\backslash pi\}\{17\}\; =\; \backslash frac\{1\}\{8\}$
\sqrt{2 \left(
2\sqrt{\sqrt{\frac{17(17-\sqrt{17})}{2}}-\sqrt{\frac{17-\sqrt{17}}{2}}-4\sqrt{2(17+\sqrt{17})} + 3\sqrt{17}+17}+\sqrt{2(17-\sqrt{17})}+\sqrt{17}+15 \right)}

А я то на самом деле скорпиошка))))

Фотографии Стесняшка :

Я позитивный и общительный человечек=)