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, 15 2015 . 07:25 +
SELECT DISTINCTROW ., Sum(.) AS [Sum-], Sum(.) AS [Sum-] FROM ( INNER JOIN ON .[] = .[]) INNER JOIN ON .[] = .[] WHERE ((.) >= :Date1) And ((.) <= :Date2) GROUP BY ..

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http://www.sql.ru/forum/1161440/pomogite-sostavit-shemu-algoritma


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