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Ñòàòèñòèêà LiveInternet.ru: ïîêàçàíî êîëè÷åñòâî õèòîâ è ïîñåòèòåëåé
Ñîçäàí: 16.03.2006
Çàïèñåé:
Êîììåíòàðèåâ:
Íàïèñàíî: 4


Îïòèìèçèðîâàòü çàïðîñ

Ñóááîòà, 18 ßíâàðÿ 2014 ã. 14:43 + â öèòàòíèê
Âñåì ïðèâåò :-)

Ïîäñêàæèòå, ïëèç, ìîæíî ëè îïòèìèçèðîâàòü òàêîé çàïðîñ:

Èìåþòñÿ äâå òàáëè÷êè - òîâàð (good) è åãî èñòîðèÿ èçìåíåíèÿ öåí (cost), íóæíî ïîëó÷èòü íàèìåíîâàíèå òîâàðà è åãî ïîñëåäíþþ öåíó.

Òàáëè÷êè:

good
------
GoodID
Name
DatePrice

cost
----
CostID
GoodID
DatePrice
Price

ß ñäåëàë òàê:
SELECT g.Name, c.DatePrice, c.Price
FROM good g INNER JOIN cost c ON g.GoodID = c.GoodID 
WHERE c.CostID IN (SELECT MAX(CostID)
                   FROM cost 
                   GROUP BY GoodID)
ORDER BY g.Name, ñ.DatePrice, c.Price ASC


Òàêîé çàïðîñ ðàáîòàåò êðàéíå äîëãî. Õîòÿ çàïèñåé â good ~5500, à â ~16500. Âðîäå íå òàê óæ è ìíîãî...

http://www.sql.ru/forum/1071739/optimizirovat-zapros


 

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