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 LiveInternet.ru:
: 16.03.2006
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: 4

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, 18 2014 . 14:43 +
:-)

, , :

- (good) (cost), .

:

good
------
GoodID
Name
DatePrice

cost
----
CostID
GoodID
DatePrice
Price

:
SELECT g.Name, c.DatePrice, c.Price
FROM good g INNER JOIN cost c ON g.GoodID = c.GoodID 
WHERE c.CostID IN (SELECT MAX(CostID)
                   FROM cost 
                   GROUP BY GoodID)
ORDER BY g.Name, .DatePrice, c.Price ASC


. good ~5500, ~16500. ...

http://www.sql.ru/forum/1071739/optimizirovat-zapros


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